Base | Representation |
---|---|
bin | 11001100010010100110111… |
… | …100101000111011111100011 |
3 | 112201122201211020212022020001 |
4 | 121202110313211013133203 |
5 | 104210041421232100003 |
6 | 1034510303325000431 |
7 | 32441063204220316 |
oct | 3142246745073743 |
9 | 481581736768201 |
10 | 112310032300003 |
11 | 328704653537aa |
12 | 1071a52a6b3117 |
13 | 4a88a37c50705 |
14 | 1da3b980a297d |
15 | ceb6959dc61d |
hex | 6625379477e3 |
112310032300003 has 2 divisors, whose sum is σ = 112310032300004. Its totient is φ = 112310032300002.
The previous prime is 112310032299977. The next prime is 112310032300013. The reversal of 112310032300003 is 300003230013211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112310032300003 is a prime.
It is a super-2 number, since 2×1123100323000032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112310032300013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56155016150001 + 56155016150002.
It is an arithmetic number, because the mean of its divisors is an integer number (56155016150002).
Almost surely, 2112310032300003 is an apocalyptic number.
112310032300003 is a deficient number, since it is larger than the sum of its proper divisors (1).
112310032300003 is an equidigital number, since it uses as much as digits as its factorization.
112310032300003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 112310032300003 its reverse (300003230013211), we get a palindrome (412313262313214).
The spelling of 112310032300003 in words is "one hundred twelve trillion, three hundred ten billion, thirty-two million, three hundred thousand, three".
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