112311111000133 has 2 divisors, whose sum is σ = 112311111000134. Its totient is φ = 112311111000132.

The previous prime is 112311111000091. The next prime is 112311111000199. The reversal of 112311111000133 is 331000111113211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77965685913124 + 34345425087009 = 8829818^2 + 5860497^2 .

It is an emirp because it is prime and its reverse (331000111113211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112311111000133 - 2³⁷ = 112173672046661 is a prime.

It is a super-2 number, since 2×112311111000133² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 112311111000133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112311111000733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56155555500066 + 56155555500067.

It is an arithmetic number, because the mean of its divisors is an integer number (56155555500067).

Almost surely, 2^{112311111000133} is an apocalyptic number.

It is an amenable number.

112311111000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

112311111000133 is an equidigital number, since it uses as much as digits as its factorization.

112311111000133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 112311111000133 its reverse (331000111113211), we get a palindrome (443311222113344).

The spelling of 112311111000133 in words is "one hundred twelve trillion, three hundred eleven billion, one hundred eleven million, one hundred thirty-three", and thus it is an aban number.