Base | Representation |
---|---|
bin | 10000010101111110101… |
… | …101111110000111110111 |
3 | 10222100221122012121001021 |
4 | 100111332231332013313 |
5 | 121400113241210112 |
6 | 2215541205242011 |
7 | 144066526156252 |
oct | 20257655760767 |
9 | 3870848177037 |
10 | 1123112444407 |
11 | 3a3344771618 |
12 | 161800103307 |
13 | 81ba8247295 |
14 | 3c504ca6099 |
15 | 1e334ac2907 |
hex | 1057eb7e1f7 |
1123112444407 has 2 divisors, whose sum is σ = 1123112444408. Its totient is φ = 1123112444406.
The previous prime is 1123112444357. The next prime is 1123112444411. The reversal of 1123112444407 is 7044442113211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1123112444407 - 215 = 1123112411639 is a prime.
It is a super-2 number, since 2×11231124444072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123112444497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561556222203 + 561556222204.
It is an arithmetic number, because the mean of its divisors is an integer number (561556222204).
Almost surely, 21123112444407 is an apocalyptic number.
1123112444407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123112444407 is an equidigital number, since it uses as much as digits as its factorization.
1123112444407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 1123112444407 its reverse (7044442113211), we get a palindrome (8167554557618).
The spelling of 1123112444407 in words is "one trillion, one hundred twenty-three billion, one hundred twelve million, four hundred forty-four thousand, four hundred seven".
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