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1123113132049 is a prime number
BaseRepresentation
bin10000010101111110110…
…000100110000000010001
310222100221200111112022111
4100111332300212000101
5121400113430211144
62215541232105321
7144066535052116
oct20257660460021
93870850445274
101123113132049
113a33450a1217
12161800395241
1381ba842827c
143c50500490d
151e334bab534
hex1057ec26011

1123113132049 has 2 divisors, whose sum is σ = 1123113132050. Its totient is φ = 1123113132048.

The previous prime is 1123113132047. The next prime is 1123113132217. The reversal of 1123113132049 is 9402313113211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1060941200400 + 62171931649 = 1030020^2 + 249343^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123113132049 - 21 = 1123113132047 is a prime.

It is a super-2 number, since 2×11231131320492 (a number of 25 digits) contains 22 as substring.

Together with 1123113132047, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1123113132049.

It is not a weakly prime, because it can be changed into another prime (1123113132041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561556566024 + 561556566025.

It is an arithmetic number, because the mean of its divisors is an integer number (561556566025).

Almost surely, 21123113132049 is an apocalyptic number.

It is an amenable number.

1123113132049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123113132049 is an equidigital number, since it uses as much as digits as its factorization.

1123113132049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 1123113132049 in words is "one trillion, one hundred twenty-three billion, one hundred thirteen million, one hundred thirty-two thousand, forty-nine".