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1123113212953 is a prime number
BaseRepresentation
bin10000010101111110110…
…000111001110000011001
310222100221200122122021221
4100111332300321300121
5121400113440303303
62215541233532041
7144066535540024
oct20257660716031
93870850578257
101123113212953
113a3345146a86
12161800414021
1381ba8456044
143c5050261bb
151e334bc54bd
hex1057ec39c19

1123113212953 has 2 divisors, whose sum is σ = 1123113212954. Its totient is φ = 1123113212952.

The previous prime is 1123113212951. The next prime is 1123113212981. The reversal of 1123113212953 is 3592123113211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1096686483984 + 26426728969 = 1047228^2 + 162563^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123113212953 - 21 = 1123113212951 is a prime.

It is a super-2 number, since 2×11231132129532 (a number of 25 digits) contains 22 as substring.

Together with 1123113212951, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1123113212951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561556606476 + 561556606477.

It is an arithmetic number, because the mean of its divisors is an integer number (561556606477).

Almost surely, 21123113212953 is an apocalyptic number.

It is an amenable number.

1123113212953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123113212953 is an equidigital number, since it uses as much as digits as its factorization.

1123113212953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720, while the sum is 34.

The spelling of 1123113212953 in words is "one trillion, one hundred twenty-three billion, one hundred thirteen million, two hundred twelve thousand, nine hundred fifty-three".