11231140032041 has 4 divisors (see below), whose sum is σ = 11231147048784. Its totient is φ = 11231133015300.

The previous prime is 11231140032037. The next prime is 11231140032083. The reversal of 11231140032041 is 14023004113211.

11231140032041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11231140032041 - 2² = 11231140032037 is a prime.

It is a super-2 number, since 2×11231140032041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11231140031998 and 11231140032016.

It is not an unprimeable number, because it can be changed into a prime (11231140002041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197126 + ... + 4743536.

It is an arithmetic number, because the mean of its divisors is an integer number (2807786762196).

Almost surely, 2^{11231140032041} is an apocalyptic number.

It is an amenable number.

11231140032041 is a deficient number, since it is larger than the sum of its proper divisors (7016743).

11231140032041 is an equidigital number, since it uses as much as digits as its factorization.

11231140032041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7016742.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11231140032041 its reverse (14023004113211), we get a palindrome (25254144145252).

The spelling of 11231140032041 in words is "eleven trillion, two hundred thirty-one billion, one hundred forty million, thirty-two thousand, forty-one".