Base | Representation |
---|---|
bin | 1010001101101111100011… |
… | …1100000111100111111111 |
3 | 1110202200202002210120100201 |
4 | 2203123320330013213333 |
5 | 2433003020040134213 |
6 | 35515315100304331 |
7 | 2236300061345602 |
oct | 243337074074777 |
9 | 43680662716321 |
10 | 11231221021183 |
11 | 3640152518459 |
12 | 13148292420a7 |
13 | 63613aa7c957 |
14 | 2ab845d04339 |
15 | 14723aa466dd |
hex | a36f8f079ff |
11231221021183 has 2 divisors, whose sum is σ = 11231221021184. Its totient is φ = 11231221021182.
The previous prime is 11231221021151. The next prime is 11231221021199. The reversal of 11231221021183 is 38112012213211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11231221021183 - 25 = 11231221021151 is a prime.
It is a super-2 number, since 2×112312210211832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11231221022183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615610510591 + 5615610510592.
It is an arithmetic number, because the mean of its divisors is an integer number (5615610510592).
Almost surely, 211231221021183 is an apocalyptic number.
11231221021183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11231221021183 is an equidigital number, since it uses as much as digits as its factorization.
11231221021183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 28.
Adding to 11231221021183 its reverse (38112012213211), we get a palindrome (49343233234394).
The spelling of 11231221021183 in words is "eleven trillion, two hundred thirty-one billion, two hundred twenty-one million, twenty-one thousand, one hundred eighty-three".
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