11231300100001 has 4 divisors (see below), whose sum is σ = 11232239262400. Its totient is φ = 11230360937604.

The previous prime is 11231300099969. The next prime is 11231300100017. The reversal of 11231300100001 is 10000100313211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11231300100001 - 2⁵ = 11231300099969 is a prime.

It is a super-2 number, since 2×11231300100001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11231300100101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469563261 + ... + 469587178.

It is an arithmetic number, because the mean of its divisors is an integer number (2808059815600).

Almost surely, 2^{11231300100001} is an apocalyptic number.

It is an amenable number.

11231300100001 is a deficient number, since it is larger than the sum of its proper divisors (939162399).

11231300100001 is an equidigital number, since it uses as much as digits as its factorization.

11231300100001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 939162398.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11231300100001 its reverse (10000100313211), we get a palindrome (21231400413212).

The spelling of 11231300100001 in words is "eleven trillion, two hundred thirty-one billion, three hundred million, one hundred thousand, one".