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11231406050 = 252224628121
BaseRepresentation
bin10100111010111000…
…11010011111100010
31001222201212112122212
422131130122133202
5141000214443200
65054252002122
7545216243024
oct123534323742
931881775585
1011231406050
114843921667
122215460342
13109cb598c7
1478790a014
1545b04e035
hex29d71a7e2

11231406050 has 12 divisors (see below), whose sum is σ = 20890415346. Its totient is φ = 4492562400.

The previous prime is 11231406049. The next prime is 11231406061. The reversal of 11231406050 is 5060413211.

It can be written as a sum of positive squares in 3 ways, for example, as 7222110289 + 4009295761 = 84983^2 + 63319^2 .

It is a super-2 number, since 2×112314060502 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 112314011 + ... + 112314110.

Almost surely, 211231406050 is an apocalyptic number.

11231406050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11231406050 is a deficient number, since it is larger than the sum of its proper divisors (9659009296).

11231406050 is a wasteful number, since it uses less digits than its factorization.

11231406050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 224628133 (or 224628128 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 11231406050 its reverse (5060413211), we get a palindrome (16291819261).

The spelling of 11231406050 in words is "eleven billion, two hundred thirty-one million, four hundred six thousand, fifty".

Divisors: 1 2 5 10 25 50 224628121 449256242 1123140605 2246281210 5615703025 11231406050