Base | Representation |
---|---|
bin | 1010001101110010101010… |
… | …0101100100010100010101 |
3 | 1110202202220011010202121012 |
4 | 2203130222211210110111 |
5 | 2433011221304021242 |
6 | 35515533453302005 |
7 | 2236326524322434 |
oct | 243345245442425 |
9 | 43682804122535 |
10 | 11232053970197 |
11 | 364053a713375 |
12 | 1314a20194905 |
13 | 6362414caba8 |
14 | 2ab8c47a911b |
15 | 147288c2b282 |
hex | a372a964515 |
11232053970197 has 2 divisors, whose sum is σ = 11232053970198. Its totient is φ = 11232053970196.
The previous prime is 11232053970169. The next prime is 11232053970209. The reversal of 11232053970197 is 79107935023211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8495365331761 + 2736688638436 = 2914681^2 + 1654294^2 .
It is a cyclic number.
It is not a de Polignac number, because 11232053970197 - 230 = 11230980228373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11232053970107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5616026985098 + 5616026985099.
It is an arithmetic number, because the mean of its divisors is an integer number (5616026985099).
Almost surely, 211232053970197 is an apocalyptic number.
It is an amenable number.
11232053970197 is a deficient number, since it is larger than the sum of its proper divisors (1).
11232053970197 is an equidigital number, since it uses as much as digits as its factorization.
11232053970197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 714420, while the sum is 50.
The spelling of 11232053970197 in words is "eleven trillion, two hundred thirty-two billion, fifty-three million, nine hundred seventy thousand, one hundred ninety-seven".
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