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112322525450053 is a prime number
BaseRepresentation
bin11001100010100000100000…
…001110101100111101000101
3112201200221001220221002021011
4121202200200032230331011
5104210243013003400203
61034520131132322221
732442014614231312
oct3142404016547505
9481627056832234
10112322525450053
11328757964132a6
1210720a36613371
134a89c7930c4a9
141da46213b1d09
15cebb776c176d
hex6628203acf45

112322525450053 has 2 divisors, whose sum is σ = 112322525450054. Its totient is φ = 112322525450052.

The previous prime is 112322525450039. The next prime is 112322525450063. The reversal of 112322525450053 is 350054525223211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107391914082049 + 4930611368004 = 10363007^2 + 2220498^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112322525450053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112322525449988 and 112322525450015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112322525450063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56161262725026 + 56161262725027.

It is an arithmetic number, because the mean of its divisors is an integer number (56161262725027).

Almost surely, 2112322525450053 is an apocalyptic number.

It is an amenable number.

112322525450053 is a deficient number, since it is larger than the sum of its proper divisors (1).

112322525450053 is an equidigital number, since it uses as much as digits as its factorization.

112322525450053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 40.

The spelling of 112322525450053 in words is "one hundred twelve trillion, three hundred twenty-two billion, five hundred twenty-five million, four hundred fifty thousand, fifty-three".