Base | Representation |
---|---|
bin | 1010001101110011100101… |
… | …0100010101101101000101 |
3 | 1110202210112101011212121020 |
4 | 2203130321110111231011 |
5 | 2433012223041042013 |
6 | 35520014202341353 |
7 | 2236335615102033 |
oct | 243347124255505 |
9 | 43683471155536 |
10 | 11232301112133 |
11 | 3640657174802 |
12 | 1314a8aaba859 |
13 | 63628077c71a |
14 | 2ab90953d553 |
15 | 1472a0798623 |
hex | a3739515b45 |
11232301112133 has 16 divisors (see below), whose sum is σ = 15028414159680. Its totient is φ = 7462219844096.
The previous prime is 11232301112107. The next prime is 11232301112147. The reversal of 11232301112133 is 33121110323211.
11232301112133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 11232301112133 - 213 = 11232301103941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11232301112633) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1412538 + ... + 4945691.
It is an arithmetic number, because the mean of its divisors is an integer number (939275884980).
Almost surely, 211232301112133 is an apocalyptic number.
It is an amenable number.
11232301112133 is a deficient number, since it is larger than the sum of its proper divisors (3796113047547).
11232301112133 is a wasteful number, since it uses less digits than its factorization.
11232301112133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6360276.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 11232301112133 its reverse (33121110323211), we get a palindrome (44353411435344).
The spelling of 11232301112133 in words is "eleven trillion, two hundred thirty-two billion, three hundred one million, one hundred twelve thousand, one hundred thirty-three".
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