Base | Representation |
---|---|
bin | 1010001101110011100101… |
… | …0100010101101101010011 |
3 | 1110202210112101011212121202 |
4 | 2203130321110111231103 |
5 | 2433012223041042042 |
6 | 35520014202341415 |
7 | 2236335615102053 |
oct | 243347124255523 |
9 | 43683471155552 |
10 | 11232301112147 |
11 | 3640657174815 |
12 | 1314a8aaba86b |
13 | 63628077c72b |
14 | 2ab90953d563 |
15 | 1472a0798632 |
hex | a3739515b53 |
11232301112147 has 2 divisors, whose sum is σ = 11232301112148. Its totient is φ = 11232301112146.
The previous prime is 11232301112107. The next prime is 11232301112159. The reversal of 11232301112147 is 74121110323211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11232301112147 - 26 = 11232301112083 is a prime.
It is not a weakly prime, because it can be changed into another prime (11232301112107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5616150556073 + 5616150556074.
It is an arithmetic number, because the mean of its divisors is an integer number (5616150556074).
Almost surely, 211232301112147 is an apocalyptic number.
11232301112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11232301112147 is an equidigital number, since it uses as much as digits as its factorization.
11232301112147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 11232301112147 its reverse (74121110323211), we get a palindrome (85353411435358).
The spelling of 11232301112147 in words is "eleven trillion, two hundred thirty-two billion, three hundred one million, one hundred twelve thousand, one hundred forty-seven".
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