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112330101113 is a prime number
BaseRepresentation
bin110100010011101100…
…1010101000101111001
3101201221110220101012022
41220213121111011321
53320023001213423
6123334223524225
711054434051106
oct1504731250571
9351843811168
10112330101113
114370346060a
121992b159675
13a792181069
145618849aad
152dc6962dc8
hex1a27655179

112330101113 has 2 divisors, whose sum is σ = 112330101114. Its totient is φ = 112330101112.

The previous prime is 112330101071. The next prime is 112330101161. The reversal of 112330101113 is 311101033211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81194792809 + 31135308304 = 284947^2 + 176452^2 .

It is a cyclic number.

It is not a de Polignac number, because 112330101113 - 214 = 112330084729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112330101091 and 112330101100.

It is not a weakly prime, because it can be changed into another prime (112330101173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56165050556 + 56165050557.

It is an arithmetic number, because the mean of its divisors is an integer number (56165050557).

Almost surely, 2112330101113 is an apocalyptic number.

It is an amenable number.

112330101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112330101113 is an equidigital number, since it uses as much as digits as its factorization.

112330101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 112330101113 its reverse (311101033211), we get a palindrome (423431134324).

The spelling of 112330101113 in words is "one hundred twelve billion, three hundred thirty million, one hundred one thousand, one hundred thirteen".