Base | Representation |
---|---|
bin | 1010001101111010000010… |
… | …1000000011011001110111 |
3 | 1110202222000011112122001220 |
4 | 2203132200220003121313 |
5 | 2433024300242131203 |
6 | 35520502155321423 |
7 | 2236426562200005 |
oct | 243364050033167 |
9 | 43688004478056 |
10 | 11234034333303 |
11 | 36413665684a1 |
12 | 1315293450273 |
13 | 63649888b192 |
14 | 2aba317d1a75 |
15 | 147352a10653 |
hex | a37a0a03677 |
11234034333303 has 16 divisors (see below), whose sum is σ = 15630144896256. Its totient is φ = 7163647666560.
The previous prime is 11234034333299. The next prime is 11234034333419. The reversal of 11234034333303 is 30333343043211.
It is not a de Polignac number, because 11234034333303 - 22 = 11234034333299 is a prime.
It is a super-3 number, since 3×112340343333033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11234034333103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5229576 + ... + 7058082.
It is an arithmetic number, because the mean of its divisors is an integer number (976884056016).
Almost surely, 211234034333303 is an apocalyptic number.
11234034333303 is a deficient number, since it is larger than the sum of its proper divisors (4396110562953).
11234034333303 is a wasteful number, since it uses less digits than its factorization.
11234034333303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1917574.
The product of its (nonzero) digits is 69984, while the sum is 33.
Adding to 11234034333303 its reverse (30333343043211), we get a palindrome (41567377376514).
The spelling of 11234034333303 in words is "eleven trillion, two hundred thirty-four billion, thirty-four million, three hundred thirty-three thousand, three hundred three".
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