Base | Representation |
---|---|
bin | 10000010110010000100… |
… | …101111101011000101111 |
3 | 10222101201112111120101221 |
4 | 100112100211331120233 |
5 | 121401222024143002 |
6 | 2220031041044211 |
7 | 144110130166306 |
oct | 20262045753057 |
9 | 3871645446357 |
10 | 1123412334127 |
11 | 3a3488a80166 |
12 | 161884626667 |
13 | 81c25406b15 |
14 | 3c532a4b43d |
15 | 1e3510adc37 |
hex | 1059097d62f |
1123412334127 has 2 divisors, whose sum is σ = 1123412334128. Its totient is φ = 1123412334126.
The previous prime is 1123412334119. The next prime is 1123412334139. The reversal of 1123412334127 is 7214332143211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1123412334127 - 23 = 1123412334119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1123412334092 and 1123412334101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123412334227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561706167063 + 561706167064.
It is an arithmetic number, because the mean of its divisors is an integer number (561706167064).
Almost surely, 21123412334127 is an apocalyptic number.
1123412334127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123412334127 is an equidigital number, since it uses as much as digits as its factorization.
1123412334127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24192, while the sum is 34.
Adding to 1123412334127 its reverse (7214332143211), we get a palindrome (8337744477338).
The spelling of 1123412334127 in words is "one trillion, one hundred twenty-three billion, four hundred twelve million, three hundred thirty-four thousand, one hundred twenty-seven".
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