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1123412410213 = 7115822710003
BaseRepresentation
bin10000010110010000100…
…110001111111101100101
310222101201112122102202221
4100112100212033331211
5121401222034111323
62220031042432341
7144110130634162
oct20262046177545
93871645572687
101123412410213
113a3489022345
121618846626b1
1381c25432642
143c532a6b069
151e3510c655d
hex1059098ff65

1123412410213 has 4 divisors (see below), whose sum is σ = 1139235120288. Its totient is φ = 1107589700140.

The previous prime is 1123412410189. The next prime is 1123412410243. The reversal of 1123412410213 is 3120142143211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1123412410213 - 29 = 1123412409701 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1123412410243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7911354931 + ... + 7911355072.

It is an arithmetic number, because the mean of its divisors is an integer number (284808780072).

Almost surely, 21123412410213 is an apocalyptic number.

It is an amenable number.

1123412410213 is a deficient number, since it is larger than the sum of its proper divisors (15822710075).

1123412410213 is an equidigital number, since it uses as much as digits as its factorization.

1123412410213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15822710074.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1123412410213 its reverse (3120142143211), we get a palindrome (4243554553424).

The spelling of 1123412410213 in words is "one trillion, one hundred twenty-three billion, four hundred twelve million, four hundred ten thousand, two hundred thirteen".

Divisors: 1 71 15822710003 1123412410213