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112341311300 = 22521123413113
BaseRepresentation
bin110100010100000010…
…0000101111101000100
3101201222020222220200102
41220220010011331010
53320033333430200
6123335304103232
711054631250631
oct1505004057504
9351866886612
10112341311300
1143709817a29
1219932a64b18
13a7945a76ca
14561a127188
152dc79296d5
hex1a28105f44

112341311300 has 18 divisors (see below), whose sum is σ = 243780645738. Its totient is φ = 44936524480.

The previous prime is 112341311287. The next prime is 112341311351. The reversal of 112341311300 is 3113143211.

It can be written as a sum of positive squares in 3 ways, for example, as 18671036164 + 93670275136 = 136642^2 + 306056^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 561706457 + ... + 561706656.

Almost surely, 2112341311300 is an apocalyptic number.

112341311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

112341311300 is an abundant number, since it is smaller than the sum of its proper divisors (131439334438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112341311300 is a wasteful number, since it uses less digits than its factorization.

112341311300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1123413127 (or 1123413120 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 112341311300 its reverse (3113143211), we get a palindrome (115454454511).

The spelling of 112341311300 in words is "one hundred twelve billion, three hundred forty-one million, three hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1123413113 2246826226 4493652452 5617065565 11234131130 22468262260 28085327825 56170655650 112341311300