Base | Representation |
---|---|
bin | 10000010110010000101… |
… | …001010000110100100111 |
3 | 10222101201121010120101111 |
4 | 100112100221100310213 |
5 | 121401222234401132 |
6 | 2220031111405451 |
7 | 144110140434226 |
oct | 20262051206447 |
9 | 3871647116344 |
10 | 1123413200167 |
11 | 3a34895118a5 |
12 | 161884983887 |
13 | 81c2564b07b |
14 | 3c532bd4cbd |
15 | 1e3511d0647 |
hex | 10590a50d27 |
1123413200167 has 2 divisors, whose sum is σ = 1123413200168. Its totient is φ = 1123413200166.
The previous prime is 1123413200113. The next prime is 1123413200207. The reversal of 1123413200167 is 7610023143211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1123413200167 - 211 = 1123413198119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123413200267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561706600083 + 561706600084.
It is an arithmetic number, because the mean of its divisors is an integer number (561706600084).
Almost surely, 21123413200167 is an apocalyptic number.
1123413200167 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123413200167 is an equidigital number, since it uses as much as digits as its factorization.
1123413200167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 1123413200167 its reverse (7610023143211), we get a palindrome (8733436343378).
The spelling of 1123413200167 in words is "one trillion, one hundred twenty-three billion, four hundred thirteen million, two hundred thousand, one hundred sixty-seven".
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