11234140032223 has 4 divisors (see below), whose sum is σ = 11235557239600. Its totient is φ = 11232722824848.

The previous prime is 11234140032161. The next prime is 11234140032253. The reversal of 11234140032223 is 32223004143211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11234140032223 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11234140032191 and 11234140032200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11234140032253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 708591798 + ... + 708607651.

It is an arithmetic number, because the mean of its divisors is an integer number (2808889309900).

Almost surely, 2^{11234140032223} is an apocalyptic number.

11234140032223 is a deficient number, since it is larger than the sum of its proper divisors (1417207377).

11234140032223 is an equidigital number, since it uses as much as digits as its factorization.

11234140032223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1417207376.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 11234140032223 its reverse (32223004143211), we get a palindrome (43457144175434).

The spelling of 11234140032223 in words is "eleven trillion, two hundred thirty-four billion, one hundred forty million, thirty-two thousand, two hundred twenty-three".