Base | Representation |
---|---|
bin | 10100111011001110… |
… | …00100011100111011 |
3 | 1001222221010110100121 |
4 | 22131213010130323 |
5 | 141001423334410 |
6 | 5054431514111 |
7 | 545252055541 |
oct | 123547043473 |
9 | 31887113317 |
10 | 11234199355 |
11 | 484545a285 |
12 | 2216388937 |
13 | 10a05c7152 |
14 | 788035d91 |
15 | 45b4019da |
hex | 29d9c473b |
11234199355 has 8 divisors (see below), whose sum is σ = 13540428432. Its totient is φ = 8947766688.
The previous prime is 11234199323. The next prime is 11234199359. The reversal of 11234199355 is 55399143211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11234199355 - 25 = 11234199323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11234199359) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4947852 + ... + 4950121.
It is an arithmetic number, because the mean of its divisors is an integer number (1692553554).
Almost surely, 211234199355 is an apocalyptic number.
11234199355 is a deficient number, since it is larger than the sum of its proper divisors (2306229077).
11234199355 is an equidigital number, since it uses as much as digits as its factorization.
11234199355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9898205.
The product of its digits is 145800, while the sum is 43.
The spelling of 11234199355 in words is "eleven billion, two hundred thirty-four million, one hundred ninety-nine thousand, three hundred fifty-five".
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