Base | Representation |
---|---|
bin | 1010001101111010101010… |
… | …0101011100100010110011 |
3 | 1110202222102210221121200021 |
4 | 2203132222211130202303 |
5 | 2433030121031001003 |
6 | 35520530524504311 |
7 | 2236433661342040 |
oct | 243365245344263 |
9 | 43688383847607 |
10 | 11234201422003 |
11 | 364144191172a |
12 | 131531b3ab097 |
13 | 6364c4391331 |
14 | 2aba49a881c7 |
15 | 1473625182bd |
hex | a37aa95c8b3 |
11234201422003 has 8 divisors (see below), whose sum is σ = 12839549748480. Its totient is φ = 9628968697800.
The previous prime is 11234201421979. The next prime is 11234201422019. The reversal of 11234201422003 is 30022410243211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11234201422003 - 29 = 11234201421491 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11234201422063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28692223 + ... + 29081128.
It is an arithmetic number, because the mean of its divisors is an integer number (1604943718560).
Almost surely, 211234201422003 is an apocalyptic number.
11234201422003 is a deficient number, since it is larger than the sum of its proper divisors (1605348326477).
11234201422003 is an equidigital number, since it uses as much as digits as its factorization.
11234201422003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57801137.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 11234201422003 its reverse (30022410243211), we get a palindrome (41256611665214).
The spelling of 11234201422003 in words is "eleven trillion, two hundred thirty-four billion, two hundred one million, four hundred twenty-two thousand, three".
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