Base | Representation |
---|---|
bin | 1010001101111010110100… |
… | …0111111010100100010011 |
3 | 1110202222112210002102120221 |
4 | 2203132231013322210103 |
5 | 2433030212431343212 |
6 | 35520535045413511 |
7 | 2236435016346031 |
oct | 243365507724423 |
9 | 43688483072527 |
10 | 11234244012307 |
11 | 3641463961428 |
12 | 131533170a297 |
13 | 636500153bb4 |
14 | 2aba515b3551 |
15 | 14736612c807 |
hex | a37ad1fa913 |
11234244012307 has 2 divisors, whose sum is σ = 11234244012308. Its totient is φ = 11234244012306.
The previous prime is 11234244012259. The next prime is 11234244012367. The reversal of 11234244012307 is 70321044243211.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (70321044243211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11234244012307 is a prime.
It is not a weakly prime, because it can be changed into another prime (11234244012367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617122006153 + 5617122006154.
It is an arithmetic number, because the mean of its divisors is an integer number (5617122006154).
Almost surely, 211234244012307 is an apocalyptic number.
11234244012307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234244012307 is an equidigital number, since it uses as much as digits as its factorization.
11234244012307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 11234244012307 its reverse (70321044243211), we get a palindrome (81555288255518).
The spelling of 11234244012307 in words is "eleven trillion, two hundred thirty-four billion, two hundred forty-four million, twelve thousand, three hundred seven".
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