Base | Representation |
---|---|
bin | 11001100010110011111000… |
… | …010010001110100110010110 |
3 | 112201202220202211120221002120 |
4 | 121202303320102032212112 |
5 | 104211113120002402014 |
6 | 1034533451404520410 |
7 | 32443352310101046 |
oct | 3142637022164626 |
9 | 481686684527076 |
10 | 112343330122134 |
11 | 328835a2084371 |
12 | 10724a81b50106 |
13 | 4a8bc13614747 |
14 | 1da56364bb726 |
15 | cec493dd8ba9 |
hex | 662cf848e996 |
112343330122134 has 16 divisors (see below), whose sum is σ = 232434476115120. Its totient is φ = 36156474062240.
The previous prime is 112343330122097. The next prime is 112343330122201. The reversal of 112343330122134 is 431221033343211.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 112343330122095 and 112343330122104.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 322825661097 + ... + 322825661444.
It is an arithmetic number, because the mean of its divisors is an integer number (14527154757195).
Almost surely, 2112343330122134 is an apocalyptic number.
112343330122134 is an abundant number, since it is smaller than the sum of its proper divisors (120091145992986).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112343330122134 is a wasteful number, since it uses less digits than its factorization.
112343330122134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 645651322575.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 112343330122134 its reverse (431221033343211), we get a palindrome (543564363465345).
The spelling of 112343330122134 in words is "one hundred twelve trillion, three hundred forty-three billion, three hundred thirty million, one hundred twenty-two thousand, one hundred thirty-four".
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