11234333413 has 2 divisors, whose sum is σ = 11234333414. Its totient is φ = 11234333412.

The previous prime is 11234333401. The next prime is 11234333419. The reversal of 11234333413 is 31433343211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10756386369 + 477947044 = 103713^2 + 21862^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11234333413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11234333419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617166706 + 5617166707.

It is an arithmetic number, because the mean of its divisors is an integer number (5617166707).

Almost surely, 2^11234333413 is an apocalyptic number.

It is an amenable number.

11234333413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11234333413 is an equidigital number, since it uses as much as digits as its factorization.

11234333413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7776, while the sum is 28.

Adding to 11234333413 its reverse (31433343211), we get a palindrome (42667676624).

The spelling of 11234333413 in words is "eleven billion, two hundred thirty-four million, three hundred thirty-three thousand, four hundred thirteen".