Base | Representation |
---|---|
bin | 11001100010110011111101… |
… | …001100000110011111011101 |
3 | 112201202220222120102012001020 |
4 | 121202303331030012133131 |
5 | 104211113302033332031 |
6 | 1034533503504234353 |
7 | 32443354326341334 |
oct | 3142637514063735 |
9 | 481686876365036 |
10 | 112343412402141 |
11 | 32883634572578 |
12 | 10724aa560b9b9 |
13 | 4a8bc2769283b |
14 | 1da56433b8d1b |
15 | cec49b23d096 |
hex | 662cfd3067dd |
112343412402141 has 8 divisors (see below), whose sum is σ = 152246810250144. Its totient is φ = 73667811411120.
The previous prime is 112343412402119. The next prime is 112343412402167. The reversal of 112343412402141 is 141204214343211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 112343412402141 - 221 = 112343410304989 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112343412402841) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 306949214031 + ... + 306949214396.
It is an arithmetic number, because the mean of its divisors is an integer number (19030851281268).
Almost surely, 2112343412402141 is an apocalyptic number.
It is an amenable number.
112343412402141 is a deficient number, since it is larger than the sum of its proper divisors (39903397848003).
112343412402141 is an equidigital number, since it uses as much as digits as its factorization.
112343412402141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 613898428491.
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 112343412402141 its reverse (141204214343211), we get a palindrome (253547626745352).
The spelling of 112343412402141 in words is "one hundred twelve trillion, three hundred forty-three billion, four hundred twelve million, four hundred two thousand, one hundred forty-one".
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