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1123434331302 = 23792370114623
BaseRepresentation
bin10000010110010001111…
…001110111110010100110
310222101210001220010212010
4100112101321313302212
5121401243142100202
62220033144335050
7144110515154103
oct20262171676246
93871701803763
101123434331302
113a349a434a48
1216188ba74486
1381c29b392ba
143c535935aaa
151e352ea676c
hex10591e77ca6

1123434331302 has 16 divisors (see below), whose sum is σ = 2275310039040. Its totient is φ = 369737881032.

The previous prime is 1123434331273. The next prime is 1123434331307. The reversal of 1123434331302 is 2031334343211.

It is a self number, because there is not a number n which added to its sum of digits gives 1123434331302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1123434331307) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1185056838 + ... + 1185057785.

It is an arithmetic number, because the mean of its divisors is an integer number (142206877440).

Almost surely, 21123434331302 is an apocalyptic number.

1123434331302 is an abundant number, since it is smaller than the sum of its proper divisors (1151875707738).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1123434331302 is a wasteful number, since it uses less digits than its factorization.

1123434331302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2370114707.

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 1123434331302 its reverse (2031334343211), we get a palindrome (3154768674513).

The spelling of 1123434331302 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-four million, three hundred thirty-one thousand, three hundred two".

Divisors: 1 2 3 6 79 158 237 474 2370114623 4740229246 7110343869 14220687738 187239055217 374478110434 561717165651 1123434331302