11234350213305 has 16 divisors (see below), whose sum is σ = 17975202670080. Its totient is φ = 5991572670848.

The previous prime is 11234350213301. The next prime is 11234350213453. The reversal of 11234350213305 is 50331205343211.

It is a cyclic number.

It is not a de Polignac number, because 11234350213305 - 2² = 11234350213301 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11234350213301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3890217 + ... + 6132086.

It is an arithmetic number, because the mean of its divisors is an integer number (1123450166880).

Almost surely, 2^{11234350213305} is an apocalyptic number.

11234350213305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11234350213305 is a deficient number, since it is larger than the sum of its proper divisors (6740852456775).

11234350213305 is a wasteful number, since it uses less digits than its factorization.

11234350213305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10097040.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 11234350213305 its reverse (50331205343211), we get a palindrome (61565555556516).

The spelling of 11234350213305 in words is "eleven trillion, two hundred thirty-four billion, three hundred fifty million, two hundred thirteen thousand, three hundred five".