Base | Representation |
---|---|
bin | 1010001101111011011100… |
… | …0100111110010011100011 |
3 | 1110202222222102022221221122 |
4 | 2203132313010332103203 |
5 | 2433031033204411342 |
6 | 35521003413042455 |
7 | 2236442115004364 |
oct | 243366704762343 |
9 | 43688872287848 |
10 | 11234411013347 |
11 | 364153a155815 |
12 | 131537962642b |
13 | 636528926192 |
14 | 2aba69845b6b |
15 | 147375b194d2 |
hex | a37b713e4e3 |
11234411013347 has 2 divisors, whose sum is σ = 11234411013348. Its totient is φ = 11234411013346.
The previous prime is 11234411013313. The next prime is 11234411013359. The reversal of 11234411013347 is 74331011443211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11234411013347 is a prime.
It is not a weakly prime, because it can be changed into another prime (11234411813347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617205506673 + 5617205506674.
It is an arithmetic number, because the mean of its divisors is an integer number (5617205506674).
Almost surely, 211234411013347 is an apocalyptic number.
11234411013347 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234411013347 is an equidigital number, since it uses as much as digits as its factorization.
11234411013347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 11234411013347 its reverse (74331011443211), we get a palindrome (85565422456558).
The spelling of 11234411013347 in words is "eleven trillion, two hundred thirty-four billion, four hundred eleven million, thirteen thousand, three hundred forty-seven".
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