Base | Representation |
---|---|
bin | 10000010110010010011… |
… | …000000101001100111011 |
3 | 10222101210121210111000210 |
4 | 100112102120011030323 |
5 | 121401302204004210 |
6 | 2220034030202203 |
7 | 144110642366232 |
oct | 20262230051473 |
9 | 3871717714023 |
10 | 1123442250555 |
11 | 3a34a3953889 |
12 | 161892653363 |
13 | 81c2b67ca51 |
14 | 3c5369d7b19 |
15 | 1e353a1ce20 |
hex | 1059260533b |
1123442250555 has 32 divisors (see below), whose sum is σ = 1806727910400. Its totient is φ = 596096392320.
The previous prime is 1123442250551. The next prime is 1123442250563. The reversal of 1123442250555 is 5550522443211.
It is not a de Polignac number, because 1123442250555 - 22 = 1123442250551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1123442250551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51304189 + ... + 51326081.
It is an arithmetic number, because the mean of its divisors is an integer number (56460247200).
Almost surely, 21123442250555 is an apocalyptic number.
1123442250555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1123442250555 is a deficient number, since it is larger than the sum of its proper divisors (683285659845).
1123442250555 is a wasteful number, since it uses less digits than its factorization.
1123442250555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39291.
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 1123442250555 its reverse (5550522443211), we get a palindrome (6673964693766).
The spelling of 1123442250555 in words is "one trillion, one hundred twenty-three billion, four hundred forty-two million, two hundred fifty thousand, five hundred fifty-five".
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