1123443321043 has 4 divisors (see below), whose sum is σ = 1123449369120. Its totient is φ = 1123437272968.

The previous prime is 1123443321041. The next prime is 1123443321053. The reversal of 1123443321043 is 3401233443211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1123443321043 - 2¹ = 1123443321041 is a prime.

It is a super-2 number, since 2×1123443321043² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1123443320996 and 1123443321014.

It is not an unprimeable number, because it can be changed into a prime (1123443321041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2736283 + ... + 3119956.

It is an arithmetic number, because the mean of its divisors is an integer number (280862342280).

Almost surely, 2^{1123443321043} is an apocalyptic number.

1123443321043 is a deficient number, since it is larger than the sum of its proper divisors (6048077).

1123443321043 is an equidigital number, since it uses as much as digits as its factorization.

1123443321043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6048076.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1123443321043 its reverse (3401233443211), we get a palindrome (4524676764254).

The spelling of 1123443321043 in words is "one trillion, one hundred twenty-three billion, four hundred forty-three million, three hundred twenty-one thousand, forty-three".