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112344343443197 is a prime number
BaseRepresentation
bin11001100010110100110100…
…101011101111011011111101
3112201210000101110022222021022
4121202310310223233123331
5104211122203410140242
61034534140123513525
732443416363142625
oct3142646453573375
9481700343288238
10112344343443197
1132883a72076498
12107251053888a5
134a8c045536cc8
141da56d0cd5885
15cec502d4c0d2
hex662d34aef6fd

112344343443197 has 2 divisors, whose sum is σ = 112344343443198. Its totient is φ = 112344343443196.

The previous prime is 112344343443089. The next prime is 112344343443217. The reversal of 112344343443197 is 791344343443211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98193949029796 + 14150394413401 = 9909286^2 + 3761701^2 .

It is a cyclic number.

It is not a de Polignac number, because 112344343443197 - 224 = 112344326665981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112344343443697) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56172171721598 + 56172171721599.

It is an arithmetic number, because the mean of its divisors is an integer number (56172171721599).

Almost surely, 2112344343443197 is an apocalyptic number.

It is an amenable number.

112344343443197 is a deficient number, since it is larger than the sum of its proper divisors (1).

112344343443197 is an equidigital number, since it uses as much as digits as its factorization.

112344343443197 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10450944, while the sum is 53.

The spelling of 112344343443197 in words is "one hundred twelve trillion, three hundred forty-four billion, three hundred forty-three million, four hundred forty-three thousand, one hundred ninety-seven".