Base | Representation |
---|---|
bin | 10000010110010010100… |
… | …000010100101110111011 |
3 | 10222101210202212021001020 |
4 | 100112102200110232323 |
5 | 121401303232130243 |
6 | 2220034144353523 |
7 | 144110666635653 |
oct | 20262240245673 |
9 | 3871722767036 |
10 | 1123444411323 |
11 | 3a34a509a243 |
12 | 1618933158a3 |
13 | 81c2bc58400 |
14 | 3c536ddb363 |
15 | 1e353ce8283 |
hex | 10592814bbb |
1123444411323 has 48 divisors (see below), whose sum is σ = 1663191986400. Its totient is φ = 673832140800.
The previous prime is 1123444411319. The next prime is 1123444411337. The reversal of 1123444411323 is 3231144443211.
It is a happy number.
It is not a de Polignac number, because 1123444411323 - 22 = 1123444411319 is a prime.
It is a super-2 number, since 2×11234444113232 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1123444411303) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 21779803 + ... + 21831323.
It is an arithmetic number, because the mean of its divisors is an integer number (34649833050).
Almost surely, 21123444411323 is an apocalyptic number.
1123444411323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1123444411323 is a deficient number, since it is larger than the sum of its proper divisors (539747575077).
1123444411323 is a wasteful number, since it uses less digits than its factorization.
1123444411323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52640 (or 52627 counting only the distinct ones).
The product of its digits is 27648, while the sum is 33.
Adding to 1123444411323 its reverse (3231144443211), we get a palindrome (4354588854534).
The spelling of 1123444411323 in words is "one trillion, one hundred twenty-three billion, four hundred forty-four million, four hundred eleven thousand, three hundred twenty-three".
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