Search a number
-
+
112344545035 = 537607267811
BaseRepresentation
bin110100010100001000…
…0011011011100001011
3101201222111002012112101
41220220100123130023
53320040200420120
6123335501254231
711055000606502
oct1505020333413
9351874065471
10112344545035
1143710626538
1219933b64377
13a79516a568
14561a729839
152dc7d6790a
hex1a2841b70b

112344545035 has 8 divisors (see below), whose sum is σ = 138457061136. Its totient is φ = 87446564640.

The previous prime is 112344545017. The next prime is 112344545069. The reversal of 112344545035 is 530545443211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 112344545035 - 221 = 112342447883 is a prime.

It is a super-2 number, since 2×1123445450352 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (37).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112344544985 and 112344545003.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 303633721 + ... + 303634090.

It is an arithmetic number, because the mean of its divisors is an integer number (17307132642).

Almost surely, 2112344545035 is an apocalyptic number.

112344545035 is a deficient number, since it is larger than the sum of its proper divisors (26112516101).

112344545035 is an equidigital number, since it uses as much as digits as its factorization.

112344545035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 607267853.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 112344545035 its reverse (530545443211), we get a palindrome (642889988246).

The spelling of 112344545035 in words is "one hundred twelve billion, three hundred forty-four million, five hundred forty-five thousand, thirty-five".

Divisors: 1 5 37 185 607267811 3036339055 22468909007 112344545035