11234504513 has 2 divisors, whose sum is σ = 11234504514. Its totient is φ = 11234504512.

The previous prime is 11234504473. The next prime is 11234504531. The reversal of 11234504513 is 31540543211.

11234504513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (11234504531) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7778005249 + 3456499264 = 88193^2 + 58792^2 .

It is an emirp because it is prime and its reverse (31540543211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11234504513 - 2¹⁶ = 11234438977 is a prime.

It is not a weakly prime, because it can be changed into another prime (11234504573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617252256 + 5617252257.

It is an arithmetic number, because the mean of its divisors is an integer number (5617252257).

Almost surely, 2^11234504513 is an apocalyptic number.

It is an amenable number.

11234504513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11234504513 is an equidigital number, since it uses as much as digits as its factorization.

11234504513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

The spelling of 11234504513 in words is "eleven billion, two hundred thirty-four million, five hundred four thousand, five hundred thirteen".