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11234511051223 = 97115819701559
BaseRepresentation
bin1010001101111011110100…
…0010100101100111010111
31110210000020101120102010011
42203132331002211213113
52433031234312114343
635521021345141051
72236444441215115
oct243367502454727
943700211512104
1011234511051223
113641590672749
1213153a702a787
13636543580ca5
142aba78c46ab5
1514737e7ca29d
hexa37bd0a59d7

11234511051223 has 4 divisors (see below), whose sum is σ = 11350330752880. Its totient is φ = 11118691349568.

The previous prime is 11234511051191. The next prime is 11234511051263. The reversal of 11234511051223 is 32215011543211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11234511051223 - 25 = 11234511051191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11234511051263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57909850683 + ... + 57909850876.

It is an arithmetic number, because the mean of its divisors is an integer number (2837582688220).

Almost surely, 211234511051223 is an apocalyptic number.

11234511051223 is a deficient number, since it is larger than the sum of its proper divisors (115819701657).

11234511051223 is an equidigital number, since it uses as much as digits as its factorization.

11234511051223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115819701656.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 11234511051223 its reverse (32215011543211), we get a palindrome (43449522594434).

The spelling of 11234511051223 in words is "eleven trillion, two hundred thirty-four billion, five hundred eleven million, fifty-one thousand, two hundred twenty-three".

Divisors: 1 97 115819701559 11234511051223