Base | Representation |
---|---|
bin | 10100111011010000… |
… | …11011001011001010 |
3 | 1001222221210111121201 |
4 | 22131220123023022 |
5 | 141002021221240 |
6 | 5054443254414 |
7 | 545255065261 |
oct | 123550331312 |
9 | 31887714551 |
10 | 11234554570 |
11 | 4845682148 |
12 | 221651a40a |
13 | 10a06bca35 |
14 | 7880c95d8 |
15 | 45b471d9a |
hex | 29da1b2ca |
11234554570 has 32 divisors (see below), whose sum is σ = 20791323648. Its totient is φ = 4367613888.
The previous prime is 11234554553. The next prime is 11234554571. The reversal of 11234554570 is 7545543211.
11234554570 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is not an unprimeable number, because it can be changed into a prime (11234554571) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 334359 + ... + 366421.
It is an arithmetic number, because the mean of its divisors is an integer number (649728864).
Almost surely, 211234554570 is an apocalyptic number.
11234554570 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11234554570 is a deficient number, since it is larger than the sum of its proper divisors (9556769078).
11234554570 is a wasteful number, since it uses less digits than its factorization.
11234554570 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33054.
The product of its (nonzero) digits is 84000, while the sum is 37.
The spelling of 11234554570 in words is "eleven billion, two hundred thirty-four million, five hundred fifty-four thousand, five hundred seventy".
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