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112346315204401 is a prime number
BaseRepresentation
bin11001100010110110101010…
…001101011010011100110001
3112201210012110212112211011001
4121202312222031122130301
5104211140223143020101
61034535103521322001
732443516264632565
oct3142665215323461
9481705425484131
10112346315204401
1132884894085903
1210725575796301
134a8c29aba4c05
141da583ab1d6a5
15cec5baed2901
hex662daa35a731

112346315204401 has 2 divisors, whose sum is σ = 112346315204402. Its totient is φ = 112346315204400.

The previous prime is 112346315204363. The next prime is 112346315204411. The reversal of 112346315204401 is 104402513643211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112290050890000 + 56264314401 = 10596700^2 + 237201^2 .

It is a cyclic number.

It is not a de Polignac number, because 112346315204401 - 27 = 112346315204273 is a prime.

It is not a weakly prime, because it can be changed into another prime (112346315204411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56173157602200 + 56173157602201.

It is an arithmetic number, because the mean of its divisors is an integer number (56173157602201).

Almost surely, 2112346315204401 is an apocalyptic number.

It is an amenable number.

112346315204401 is a deficient number, since it is larger than the sum of its proper divisors (1).

112346315204401 is an equidigital number, since it uses as much as digits as its factorization.

112346315204401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 37.

Adding to 112346315204401 its reverse (104402513643211), we get a palindrome (216748828847612).

The spelling of 112346315204401 in words is "one hundred twelve trillion, three hundred forty-six billion, three hundred fifteen million, two hundred four thousand, four hundred one".