Base | Representation |
---|---|
bin | 11001100010111010001101… |
… | …101010110000100110100001 |
3 | 112201210120022211020211221210 |
4 | 121202322031222300212201 |
5 | 104211221032104402340 |
6 | 1034540534322140333 |
7 | 32444012663263614 |
oct | 3142721552604641 |
9 | 481716284224853 |
10 | 112350131325345 |
11 | 32886472197a71 |
12 | 1072625b7b16a9 |
13 | 4a8c758694c44 |
14 | 1da5abd88a17b |
15 | cec741035180 |
hex | 662e8dab09a1 |
112350131325345 has 16 divisors (see below), whose sum is σ = 179924976608832. Its totient is φ = 59865147877440.
The previous prime is 112350131325269. The next prime is 112350131325347. The reversal of 112350131325345 is 543523131053211.
It is a happy number.
It is not a de Polignac number, because 112350131325345 - 221 = 112350129228193 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (112350131325347) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3432618262 + ... + 3432650991.
It is an arithmetic number, because the mean of its divisors is an integer number (11245311038052).
Almost surely, 2112350131325345 is an apocalyptic number.
112350131325345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
112350131325345 is a deficient number, since it is larger than the sum of its proper divisors (67574845283487).
112350131325345 is a wasteful number, since it uses less digits than its factorization.
112350131325345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6865270352.
The product of its (nonzero) digits is 162000, while the sum is 39.
Adding to 112350131325345 its reverse (543523131053211), we get a palindrome (655873262378556).
The spelling of 112350131325345 in words is "one hundred twelve trillion, three hundred fifty billion, one hundred thirty-one million, three hundred twenty-five thousand, three hundred forty-five".
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