Base | Representation |
---|---|
bin | 1010001110010000011011… |
… | …0010011111011111110110 |
3 | 1110210112111221111102202202 |
4 | 2203210012302133133312 |
5 | 2433124102042010032 |
6 | 35523334332504502 |
7 | 2240031515525450 |
oct | 243440662373766 |
9 | 43715457442682 |
10 | 11240043313142 |
11 | 364396a471a36 |
12 | 131648b91b132 |
13 | 636c1577c357 |
14 | 2ac04189b2d0 |
15 | 1475a531dd62 |
hex | a3906c9f7f6 |
11240043313142 has 64 divisors (see below), whose sum is σ = 20142061185024. Its totient is φ = 4599554319360.
The previous prime is 11240043313141. The next prime is 11240043313181. The reversal of 11240043313142 is 24131334004211.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11240043313141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1211598608 + ... + 1211607884.
It is an arithmetic number, because the mean of its divisors is an integer number (314719706016).
Almost surely, 211240043313142 is an apocalyptic number.
11240043313142 is a deficient number, since it is larger than the sum of its proper divisors (8902017871882).
11240043313142 is a wasteful number, since it uses less digits than its factorization.
11240043313142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15573.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11240043313142 its reverse (24131334004211), we get a palindrome (35371377317353).
The spelling of 11240043313142 in words is "eleven trillion, two hundred forty billion, forty-three million, three hundred thirteen thousand, one hundred forty-two".
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