Base | Representation |
---|---|
bin | 11001100011101100011011… |
… | …000111010010101100010111 |
3 | 112201222201111002110111012121 |
4 | 121203230123013102230113 |
5 | 104213111440231000043 |
6 | 1035021412134000411 |
7 | 32450631665410306 |
oct | 3143543307225427 |
9 | 481881432414177 |
10 | 112404044000023 |
11 | 328a731851a456 |
12 | 107347a6aa6107 |
13 | 4a9486ac2c989 |
14 | 1da8555abc43d |
15 | cedd49150ded |
hex | 663b1b1d2b17 |
112404044000023 has 2 divisors, whose sum is σ = 112404044000024. Its totient is φ = 112404044000022.
The previous prime is 112404044000009. The next prime is 112404044000273. The reversal of 112404044000023 is 320000440404211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112404044000023 - 213 = 112404043991831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112404044000723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56202022000011 + 56202022000012.
It is an arithmetic number, because the mean of its divisors is an integer number (56202022000012).
Almost surely, 2112404044000023 is an apocalyptic number.
112404044000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
112404044000023 is an equidigital number, since it uses as much as digits as its factorization.
112404044000023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 112404044000023 its reverse (320000440404211), we get a palindrome (432404484404234).
The spelling of 112404044000023 in words is "one hundred twelve trillion, four hundred four billion, forty-four million, twenty-three", and thus it is an aban number.
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