Base | Representation |
---|---|
bin | 10000010110111001100… |
… | …101100101101111100101 |
3 | 10222110111110122212010101 |
4 | 100112321211211233211 |
5 | 121404124111300031 |
6 | 2220223210224101 |
7 | 144133151136631 |
oct | 20267145455745 |
9 | 3873443585111 |
10 | 1124100103141 |
11 | 3a3801226204 |
12 | 161a36a25031 |
13 | 82004a53032 |
14 | 3c59a11ddc1 |
15 | 1e391667361 |
hex | 105b9965be5 |
1124100103141 has 2 divisors, whose sum is σ = 1124100103142. Its totient is φ = 1124100103140.
The previous prime is 1124100103127. The next prime is 1124100103183. The reversal of 1124100103141 is 1413010014211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1105118152516 + 18981950625 = 1051246^2 + 137775^2 .
It is a cyclic number.
It is not a de Polignac number, because 1124100103141 - 217 = 1124099972069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1124100103111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562050051570 + 562050051571.
It is an arithmetic number, because the mean of its divisors is an integer number (562050051571).
Almost surely, 21124100103141 is an apocalyptic number.
It is an amenable number.
1124100103141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124100103141 is an equidigital number, since it uses as much as digits as its factorization.
1124100103141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1124100103141 its reverse (1413010014211), we get a palindrome (2537110117352).
The spelling of 1124100103141 in words is "one trillion, one hundred twenty-four billion, one hundred million, one hundred three thousand, one hundred forty-one".
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