1124101143133 has 4 divisors (see below), whose sum is σ = 1124104136128. Its totient is φ = 1124098150140.

The previous prime is 1124101143097. The next prime is 1124101143229. The reversal of 1124101143133 is 3313411014211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1124101143133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1124101143098 and 1124101143107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1124101140133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 835941 + ... + 1716682.

It is an arithmetic number, because the mean of its divisors is an integer number (281026034032).

Almost surely, 2^{1124101143133} is an apocalyptic number.

It is an amenable number.

1124101143133 is a deficient number, since it is larger than the sum of its proper divisors (2992995).

1124101143133 is an equidigital number, since it uses as much as digits as its factorization.

1124101143133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2992994.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1124101143133 its reverse (3313411014211), we get a palindrome (4437512157344).

The spelling of 1124101143133 in words is "one trillion, one hundred twenty-four billion, one hundred one million, one hundred forty-three thousand, one hundred thirty-three".