Base | Representation |
---|---|
bin | 110100010110000101… |
… | …0100100111111001111 |
3 | 101202011001110202200002 |
4 | 1220230022210333033 |
5 | 3320203442321033 |
6 | 123350202554515 |
7 | 11056425153536 |
oct | 1505412447717 |
9 | 352131422602 |
10 | 112410120143 |
11 | 43744645042 |
12 | 19951b08a3b |
13 | a7a5919cb9 |
14 | 562531931d |
15 | 2dcd9bc3e8 |
hex | 1a2c2a4fcf |
112410120143 has 2 divisors, whose sum is σ = 112410120144. Its totient is φ = 112410120142.
The previous prime is 112410120133. The next prime is 112410120161. The reversal of 112410120143 is 341021014211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112410120143 - 26 = 112410120079 is a prime.
It is a super-2 number, since 2×1124101201432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112410120133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56205060071 + 56205060072.
It is an arithmetic number, because the mean of its divisors is an integer number (56205060072).
Almost surely, 2112410120143 is an apocalyptic number.
112410120143 is a deficient number, since it is larger than the sum of its proper divisors (1).
112410120143 is an equidigital number, since it uses as much as digits as its factorization.
112410120143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 112410120143 its reverse (341021014211), we get a palindrome (453431134354).
The spelling of 112410120143 in words is "one hundred twelve billion, four hundred ten million, one hundred twenty thousand, one hundred forty-three".
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