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11241143431 = 73904341131
BaseRepresentation
bin10100111100000011…
…00011110010000111
31002000102012020211121
422132001203302013
5141010213042211
65055240414411
7545365066630
oct123601436207
932012166747
1011241143431
114849372491
122218777407
1310a1b88a7b
14788d22887
1545bd24271
hex29e063c87

11241143431 has 8 divisors (see below), whose sum is σ = 12847662464. Its totient is φ = 9634784760.

The previous prime is 11241143423. The next prime is 11241143443. The reversal of 11241143431 is 13434114211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11241143431 - 23 = 11241143423 is a prime.

It is a super-2 number, since 2×112411434312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11241143396 and 11241143405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11241143401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 252736 + ... + 293866.

It is an arithmetic number, because the mean of its divisors is an integer number (1605957808).

Almost surely, 211241143431 is an apocalyptic number.

11241143431 is a deficient number, since it is larger than the sum of its proper divisors (1606519033).

11241143431 is an equidigital number, since it uses as much as digits as its factorization.

11241143431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80181.

The product of its digits is 1152, while the sum is 25.

Adding to 11241143431 its reverse (13434114211), we get a palindrome (24675257642).

The spelling of 11241143431 in words is "eleven billion, two hundred forty-one million, one hundred forty-three thousand, four hundred thirty-one".

Divisors: 1 7 39043 41131 273301 287917 1605877633 11241143431