Search a number
-
+
1124212243313 is a prime number
BaseRepresentation
bin10000010111000000010…
…001010111101101110001
310222110210021200011112002
4100113000101113231301
5121404341313241223
62220242253543345
7144136012254125
oct20270021275561
93873707604462
101124212243313
113a3859559835
12161a684a4b55
1382022057573
143c5aad91585
151e39b418e28
hex105c0457b71

1124212243313 has 2 divisors, whose sum is σ = 1124212243314. Its totient is φ = 1124212243312.

The previous prime is 1124212243291. The next prime is 1124212243331. The reversal of 1124212243313 is 3133422124211.

It is a happy number.

Together with next prime (1124212243331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 888707800369 + 235504442944 = 942713^2 + 485288^2 .

It is a cyclic number.

It is not a de Polignac number, because 1124212243313 - 28 = 1124212243057 is a prime.

It is not a weakly prime, because it can be changed into another prime (1124212249313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562106121656 + 562106121657.

It is an arithmetic number, because the mean of its divisors is an integer number (562106121657).

Almost surely, 21124212243313 is an apocalyptic number.

It is an amenable number.

1124212243313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124212243313 is an equidigital number, since it uses as much as digits as its factorization.

1124212243313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 29.

Adding to 1124212243313 its reverse (3133422124211), we get a palindrome (4257634367524).

The spelling of 1124212243313 in words is "one trillion, one hundred twenty-four billion, two hundred twelve million, two hundred forty-three thousand, three hundred thirteen".