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11242202044141 is a prime number
BaseRepresentation
bin1010001110011000011101…
…1101011001011011101101
31110210202002101112022222201
42203212013131121123231
52433143012210403031
635524332445541501
72240136150453025
oct243460735313355
943722071468881
1011242202044141
113644877a74542
121316992874891
1363719aa91683
142ac1a8474a85
1514767ead7d61
hexa39877596ed

11242202044141 has 2 divisors, whose sum is σ = 11242202044142. Its totient is φ = 11242202044140.

The previous prime is 11242202044111. The next prime is 11242202044147. The reversal of 11242202044141 is 14144020224211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9772157342025 + 1470044702116 = 3126045^2 + 1212454^2 .

It is a cyclic number.

It is not a de Polignac number, because 11242202044141 - 29 = 11242202043629 is a prime.

It is a super-3 number, since 3×112422020441413 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11242202044147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621101022070 + 5621101022071.

It is an arithmetic number, because the mean of its divisors is an integer number (5621101022071).

Almost surely, 211242202044141 is an apocalyptic number.

It is an amenable number.

11242202044141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11242202044141 is an equidigital number, since it uses as much as digits as its factorization.

11242202044141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4096, while the sum is 28.

Adding to 11242202044141 its reverse (14144020224211), we get a palindrome (25386222268352).

The spelling of 11242202044141 in words is "eleven trillion, two hundred forty-two billion, two hundred two million, forty-four thousand, one hundred forty-one".