11242425433 has 2 divisors, whose sum is σ = 11242425434. Its totient is φ = 11242425432.

The previous prime is 11242425391. The next prime is 11242425463. The reversal of 11242425433 is 33452424211.

11242425433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6789265609 + 4453159824 = 82397^2 + 66732^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11242425433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11242425395 and 11242425404.

It is not a weakly prime, because it can be changed into another prime (11242425463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621212716 + 5621212717.

It is an arithmetic number, because the mean of its divisors is an integer number (5621212717).

Almost surely, 2^11242425433 is an apocalyptic number.

It is an amenable number.

11242425433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11242425433 is an equidigital number, since it uses as much as digits as its factorization.

11242425433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23040, while the sum is 31.

Adding to 11242425433 its reverse (33452424211), we get a palindrome (44694849644).

The spelling of 11242425433 in words is "eleven billion, two hundred forty-two million, four hundred twenty-five thousand, four hundred thirty-three".