Base | Representation |
---|---|
bin | 1010001110011010011100… |
… | …0111010010010011001011 |
3 | 1110210210110101211201021121 |
4 | 2203212213013102103023 |
5 | 2433200104134244132 |
6 | 35524501300420111 |
7 | 2240155256512201 |
oct | 243464707222313 |
9 | 43723411751247 |
10 | 11242733118667 |
11 | 364501a825706 |
12 | 1316b006a7637 |
13 | 637253b0685b |
14 | 2ac218bd9071 |
15 | 1476b153d497 |
hex | a39a71d24cb |
11242733118667 has 2 divisors, whose sum is σ = 11242733118668. Its totient is φ = 11242733118666.
The previous prime is 11242733118571. The next prime is 11242733118697. The reversal of 11242733118667 is 76681133724211.
It is a happy number.
11242733118667 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (76681133724211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11242733118667 is a prime.
It is not a weakly prime, because it can be changed into another prime (11242733118697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621366559333 + 5621366559334.
It is an arithmetic number, because the mean of its divisors is an integer number (5621366559334).
Almost surely, 211242733118667 is an apocalyptic number.
11242733118667 is a deficient number, since it is larger than the sum of its proper divisors (1).
11242733118667 is an equidigital number, since it uses as much as digits as its factorization.
11242733118667 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2032128, while the sum is 52.
The spelling of 11242733118667 in words is "eleven trillion, two hundred forty-two billion, seven hundred thirty-three million, one hundred eighteen thousand, six hundred sixty-seven".
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