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1124300107433 is a prime number
BaseRepresentation
bin10000010111000101100…
…000100010111010101001
310222111000102000010102202
4100113011200202322221
5121410031311414213
62220255113105545
7144141130142546
oct20270540427251
93874012003382
101124300107433
113a38a4111408
12161a919b82b5
138203730c279
143c5b8903bcd
151e3a3ec2b58
hex105c5822ea9

1124300107433 has 2 divisors, whose sum is σ = 1124300107434. Its totient is φ = 1124300107432.

The previous prime is 1124300107253. The next prime is 1124300107439. The reversal of 1124300107433 is 3347010034211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 862143819289 + 262156288144 = 928517^2 + 512012^2 .

It is an emirp because it is prime and its reverse (3347010034211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1124300107433 - 224 = 1124283330217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1124300107396 and 1124300107405.

It is not a weakly prime, because it can be changed into another prime (1124300107439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562150053716 + 562150053717.

It is an arithmetic number, because the mean of its divisors is an integer number (562150053717).

Almost surely, 21124300107433 is an apocalyptic number.

It is an amenable number.

1124300107433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124300107433 is an equidigital number, since it uses as much as digits as its factorization.

1124300107433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

The spelling of 1124300107433 in words is "one trillion, one hundred twenty-four billion, three hundred million, one hundred seven thousand, four hundred thirty-three".